7(x-15)=4(x+12)

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Solution for 7(x-15)=4(x+12) equation:



7(x-15)=4(x+12)
We move all terms to the left:
7(x-15)-(4(x+12))=0
We multiply parentheses
7x-(4(x+12))-105=0
We calculate terms in parentheses: -(4(x+12)), so:
4(x+12)
We multiply parentheses
4x+48
Back to the equation:
-(4x+48)
We get rid of parentheses
7x-4x-48-105=0
We add all the numbers together, and all the variables
3x-153=0
We move all terms containing x to the left, all other terms to the right
3x=153
x=153/3
x=51

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