7(x-11)+67=3(x+12)-10

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Solution for 7(x-11)+67=3(x+12)-10 equation: 



7(x-11)+67=3(x+12)-10

We move all terms to the left:

7(x-11)+67-(3(x+12)-10)=0

We multiply parentheses

7x-(3(x+12)-10)-77+67=0



We calculate terms in parentheses: -(3(x+12)-10), so:

3(x+12)-10

We multiply parentheses

3x+36-10

We add all the numbers together, and all the variables

3x+26

Back to the equation:

-(3x+26)



We add all the numbers together, and all the variables

7x-(3x+26)-10=0

We get rid of parentheses

7x-3x-26-10=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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