7(x+5)-1=2(x-3)+x

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Solution for 7(x+5)-1=2(x-3)+x equation: 



7(x+5)-1=2(x-3)+x

We move all terms to the left:

7(x+5)-1-(2(x-3)+x)=0

We multiply parentheses

7x-(2(x-3)+x)+35-1=0



We calculate terms in parentheses: -(2(x-3)+x), so:

2(x-3)+x

We add all the numbers together, and all the variables

x+2(x-3)

We multiply parentheses

x+2x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

7x-(3x-6)+34=0

We get rid of parentheses

7x-3x+6+34=0

We add all the numbers together, and all the variables

4x+40=0

We move all terms containing x to the left, all other terms to the right

4x=-40

x=-40/4

x=-10

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