7(x+5)+2=3x+4x+40-3

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Solution for 7(x+5)+2=3x+4x+40-3 equation: 


Simplifying
7(x + 5) + 2 = 3x + 4x + 40 + -3

Reorder the terms:
7(5 + x) + 2 = 3x + 4x + 40 + -3
(5 * 7 + x * 7) + 2 = 3x + 4x + 40 + -3
(35 + 7x) + 2 = 3x + 4x + 40 + -3

Reorder the terms:
35 + 2 + 7x = 3x + 4x + 40 + -3

Combine like terms: 35 + 2 = 37
37 + 7x = 3x + 4x + 40 + -3

Reorder the terms:
37 + 7x = 40 + -3 + 3x + 4x

Combine like terms: 40 + -3 = 37
37 + 7x = 37 + 3x + 4x

Combine like terms: 3x + 4x = 7x
37 + 7x = 37 + 7x

Add '-37' to each side of the equation.
37 + -37 + 7x = 37 + -37 + 7x

Combine like terms: 37 + -37 = 0
0 + 7x = 37 + -37 + 7x
7x = 37 + -37 + 7x

Combine like terms: 37 + -37 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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