7(x+4)=3(x+2)+3x

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Solution for 7(x+4)=3(x+2)+3x equation: 



7(x+4)=3(x+2)+3x

We move all terms to the left:

7(x+4)-(3(x+2)+3x)=0

We multiply parentheses

7x-(3(x+2)+3x)+28=0



We calculate terms in parentheses: -(3(x+2)+3x), so:

3(x+2)+3x

We add all the numbers together, and all the variables

3x+3(x+2)

We multiply parentheses

3x+3x+6

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

7x-6x-6+28=0

We add all the numbers together, and all the variables

x+22=0

We move all terms containing x to the left, all other terms to the right

x=-22

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