7(x+4)=2x+5x+28

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Solution for 7(x+4)=2x+5x+28 equation: 



7(x+4)=2x+5x+28

We move all terms to the left:

7(x+4)-(2x+5x+28)=0

We add all the numbers together, and all the variables

7(x+4)-(7x+28)=0

We multiply parentheses

7x-(7x+28)+28=0

We get rid of parentheses

7x-7x-28+28=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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