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7(x+4)+6(3-x)=8(x-3)-2(x+4)
We move all terms to the left:
7(x+4)+6(3-x)-(8(x-3)-2(x+4))=0
We add all the numbers together, and all the variables
7(x+4)+6(-1x+3)-(8(x-3)-2(x+4))=0
We multiply parentheses
7x-6x-(8(x-3)-2(x+4))+28+18=0
We calculate terms in parentheses: -(8(x-3)-2(x+4)), so:We add all the numbers together, and all the variables
8(x-3)-2(x+4)
We multiply parentheses
8x-2x-24-8
We add all the numbers together, and all the variables
6x-32
Back to the equation:
-(6x-32)
x-(6x-32)+46=0
We get rid of parentheses
x-6x+32+46=0
We add all the numbers together, and all the variables
-5x+78=0
We move all terms containing x to the left, all other terms to the right
-5x=-78
x=-78/-5
x=15+3/5
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