7(x+4)+5=11-4(x-3)

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Solution for 7(x+4)+5=11-4(x-3) equation: 



7(x+4)+5=11-4(x-3)

We move all terms to the left:

7(x+4)+5-(11-4(x-3))=0

We multiply parentheses

7x-(11-4(x-3))+28+5=0



We calculate terms in parentheses: -(11-4(x-3)), so:

11-4(x-3)

determiningTheFunctionDomain
-4(x-3)+11

We multiply parentheses

-4x+12+11

We add all the numbers together, and all the variables

-4x+23

Back to the equation:

-(-4x+23)



We add all the numbers together, and all the variables

7x-(-4x+23)+33=0

We get rid of parentheses

7x+4x-23+33=0

We add all the numbers together, and all the variables

11x+10=0

We move all terms containing x to the left, all other terms to the right

11x=-10

x=-10/11

x=-10/11

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