7(x+3)=5(x-4)+x-10

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Solution for 7(x+3)=5(x-4)+x-10 equation: 



7(x+3)=5(x-4)+x-10

We move all terms to the left:

7(x+3)-(5(x-4)+x-10)=0

We multiply parentheses

7x-(5(x-4)+x-10)+21=0



We calculate terms in parentheses: -(5(x-4)+x-10), so:

5(x-4)+x-10

We add all the numbers together, and all the variables

x+5(x-4)-10

We multiply parentheses

x+5x-20-10

We add all the numbers together, and all the variables

6x-30

Back to the equation:

-(6x-30)



We get rid of parentheses

7x-6x+30+21=0

We add all the numbers together, and all the variables

x+51=0

We move all terms containing x to the left, all other terms to the right

x=-51

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