7(x+3)-4x+1=(x+22)+(x+20)

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Solution for 7(x+3)-4x+1=(x+22)+(x+20) equation: 



7(x+3)-4x+1=(x+22)+(x+20)

We move all terms to the left:

7(x+3)-4x+1-((x+22)+(x+20))=0

We add all the numbers together, and all the variables

-4x+7(x+3)-((x+22)+(x+20))+1=0

We multiply parentheses

-4x+7x-((x+22)+(x+20))+21+1=0



We calculate terms in parentheses: -((x+22)+(x+20)), so:

(x+22)+(x+20)

We get rid of parentheses

x+x+22+20

We add all the numbers together, and all the variables

2x+42

Back to the equation:

-(2x+42)



We add all the numbers together, and all the variables

3x-(2x+42)+22=0

We get rid of parentheses

3x-2x-42+22=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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