7(x+3)+9=3(x+2)+8-x

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Solution for 7(x+3)+9=3(x+2)+8-x equation: 



7(x+3)+9=3(x+2)+8-x

We move all terms to the left:

7(x+3)+9-(3(x+2)+8-x)=0

We multiply parentheses

7x-(3(x+2)+8-x)+21+9=0



We calculate terms in parentheses: -(3(x+2)+8-x), so:

3(x+2)+8-x

determiningTheFunctionDomain
3(x+2)-x+8

We add all the numbers together, and all the variables

-1x+3(x+2)+8

We multiply parentheses

-1x+3x+6+8

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

7x-(2x+14)+30=0

We get rid of parentheses

7x-2x-14+30=0

We add all the numbers together, and all the variables

5x+16=0

We move all terms containing x to the left, all other terms to the right

5x=-16

x=-16/5

x=-3+1/5

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