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7(x+3)+9=(x-2)-3x
We move all terms to the left:
7(x+3)+9-((x-2)-3x)=0
We multiply parentheses
7x-((x-2)-3x)+21+9=0
We calculate terms in parentheses: -((x-2)-3x), so:We add all the numbers together, and all the variables
(x-2)-3x
We add all the numbers together, and all the variables
-3x+(x-2)
We get rid of parentheses
-3x+x-2
We add all the numbers together, and all the variables
-2x-2
Back to the equation:
-(-2x-2)
7x-(-2x-2)+30=0
We get rid of parentheses
7x+2x+2+30=0
We add all the numbers together, and all the variables
9x+32=0
We move all terms containing x to the left, all other terms to the right
9x=-32
x=-32/9
x=-3+5/9
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