7(x+3)+4=-3(x-2)-7

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Solution for 7(x+3)+4=-3(x-2)-7 equation: 



7(x+3)+4=-3(x-2)-7

We move all terms to the left:

7(x+3)+4-(-3(x-2)-7)=0

We multiply parentheses

7x-(-3(x-2)-7)+21+4=0



We calculate terms in parentheses: -(-3(x-2)-7), so:

-3(x-2)-7

We multiply parentheses

-3x+6-7

We add all the numbers together, and all the variables

-3x-1

Back to the equation:

-(-3x-1)



We add all the numbers together, and all the variables

7x-(-3x-1)+25=0

We get rid of parentheses

7x+3x+1+25=0

We add all the numbers together, and all the variables

10x+26=0

We move all terms containing x to the left, all other terms to the right

10x=-26

x=-26/10

x=-2+3/5

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