7(x+2)=6(x+5)x=-44x=-16x=16x=44

Solution for 7(x+2)=6(x+5)x=-44x=-16x=16x=44 equation:

7(x+2)=6(x+5)x=-44x=-16x=16x=44

We move all terms to the left:

7(x+2)-(6(x+5)x)=0

We multiply parentheses

7x-(6(x+5)x)+14=0


We calculate terms in parentheses: -(6(x+5)x), so:

6(x+5)x

We multiply parentheses

6x^2+30x

Back to the equation:

-(6x^2+30x)


We get rid of parentheses

-6x^2+7x-30x+14=0

We add all the numbers together, and all the variables

-6x^2-23x+14=0

a = -6; b = -23; c = +14;
Δ = b2-4ac
Δ = -232-4·(-6)·14
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{865}}{2*-6}=\frac{23-\sqrt{865}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{865}}{2*-6}=\frac{23+\sqrt{865}}{-12}
$