7(x+2)=3(x+12)-12

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Solution for 7(x+2)=3(x+12)-12 equation:



7(x+2)=3(x+12)-12
We move all terms to the left:
7(x+2)-(3(x+12)-12)=0
We multiply parentheses
7x-(3(x+12)-12)+14=0
We calculate terms in parentheses: -(3(x+12)-12), so:
3(x+12)-12
We multiply parentheses
3x+36-12
We add all the numbers together, and all the variables
3x+24
Back to the equation:
-(3x+24)
We get rid of parentheses
7x-3x-24+14=0
We add all the numbers together, and all the variables
4x-10=0
We move all terms containing x to the left, all other terms to the right
4x=10
x=10/4
x=2+1/2

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