7(x+2)=3(2x-6)32

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Solution for 7(x+2)=3(2x-6)32 equation: 



7(x+2)=3(2x-6)32

We move all terms to the left:

7(x+2)-(3(2x-6)32)=0

We multiply parentheses

7x-(3(2x-6)32)+14=0



We calculate terms in parentheses: -(3(2x-6)32), so:

3(2x-6)32

We multiply parentheses

192x-576

Back to the equation:

-(192x-576)



We get rid of parentheses

7x-192x+576+14=0

We add all the numbers together, and all the variables

-185x+590=0

We move all terms containing x to the left, all other terms to the right

-185x=-590

x=-590/-185

x=3+7/37

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