7(x+2)-7=4x+3(1+x)

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Solution for 7(x+2)-7=4x+3(1+x) equation:



7(x+2)-7=4x+3(1+x)
We move all terms to the left:
7(x+2)-7-(4x+3(1+x))=0
We add all the numbers together, and all the variables
7(x+2)-(4x+3(x+1))-7=0
We multiply parentheses
7x-(4x+3(x+1))+14-7=0
We calculate terms in parentheses: -(4x+3(x+1)), so:
4x+3(x+1)
We multiply parentheses
4x+3x+3
We add all the numbers together, and all the variables
7x+3
Back to the equation:
-(7x+3)
We add all the numbers together, and all the variables
7x-(7x+3)+7=0
We get rid of parentheses
7x-7x-3+7=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation

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