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7(x+2)-6=2(6x+4)
We move all terms to the left:
7(x+2)-6-(2(6x+4))=0
We multiply parentheses
7x-(2(6x+4))+14-6=0
We calculate terms in parentheses: -(2(6x+4)), so:We add all the numbers together, and all the variables
2(6x+4)
We multiply parentheses
12x+8
Back to the equation:
-(12x+8)
7x-(12x+8)+8=0
We get rid of parentheses
7x-12x-8+8=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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