7(x+1)+6=3x+4(2+x)

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Solution for 7(x+1)+6=3x+4(2+x) equation:


Simplifying
7(x + 1) + 6 = 3x + 4(2 + x)

Reorder the terms:
7(1 + x) + 6 = 3x + 4(2 + x)
(1 * 7 + x * 7) + 6 = 3x + 4(2 + x)
(7 + 7x) + 6 = 3x + 4(2 + x)

Reorder the terms:
7 + 6 + 7x = 3x + 4(2 + x)

Combine like terms: 7 + 6 = 13
13 + 7x = 3x + 4(2 + x)
13 + 7x = 3x + (2 * 4 + x * 4)
13 + 7x = 3x + (8 + 4x)

Reorder the terms:
13 + 7x = 8 + 3x + 4x

Combine like terms: 3x + 4x = 7x
13 + 7x = 8 + 7x

Add '-7x' to each side of the equation.
13 + 7x + -7x = 8 + 7x + -7x

Combine like terms: 7x + -7x = 0
13 + 0 = 8 + 7x + -7x
13 = 8 + 7x + -7x

Combine like terms: 7x + -7x = 0
13 = 8 + 0
13 = 8

Solving
13 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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