7(x+1)+3(x+1)=7x-7

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Solution for 7(x+1)+3(x+1)=7x-7 equation: 



7(x+1)+3(x+1)=7x-7

We move all terms to the left:

7(x+1)+3(x+1)-(7x-7)=0

We multiply parentheses

7x+3x-(7x-7)+7+3=0

We get rid of parentheses

7x+3x-7x+7+7+3=0

We add all the numbers together, and all the variables

3x+17=0

We move all terms containing x to the left, all other terms to the right

3x=-17

x=-17/3

x=-5+2/3

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