7(v-4)-3=-3(-9v+5)-6v

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Solution for 7(v-4)-3=-3(-9v+5)-6v equation: 



7(v-4)-3=-3(-9v+5)-6v

We move all terms to the left:

7(v-4)-3-(-3(-9v+5)-6v)=0

We multiply parentheses

7v-(-3(-9v+5)-6v)-28-3=0



We calculate terms in parentheses: -(-3(-9v+5)-6v), so:

-3(-9v+5)-6v

We add all the numbers together, and all the variables

-6v-3(-9v+5)

We multiply parentheses

-6v+27v-15

We add all the numbers together, and all the variables

21v-15

Back to the equation:

-(21v-15)



We add all the numbers together, and all the variables

7v-(21v-15)-31=0

We get rid of parentheses

7v-21v+15-31=0

We add all the numbers together, and all the variables

-14v-16=0

We move all terms containing v to the left, all other terms to the right

-14v=16

v=16/-14

v=-1+1/7

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