7(v-1)=6v+3-5(-2v-1)

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Solution for 7(v-1)=6v+3-5(-2v-1) equation: 



7(v-1)=6v+3-5(-2v-1)

We move all terms to the left:

7(v-1)-(6v+3-5(-2v-1))=0

We multiply parentheses

7v-(6v+3-5(-2v-1))-7=0



We calculate terms in parentheses: -(6v+3-5(-2v-1)), so:

6v+3-5(-2v-1)

determiningTheFunctionDomain
6v-5(-2v-1)+3

We multiply parentheses

6v+10v+5+3

We add all the numbers together, and all the variables

16v+8

Back to the equation:

-(16v+8)



We get rid of parentheses

7v-16v-8-7=0

We add all the numbers together, and all the variables

-9v-15=0

We move all terms containing v to the left, all other terms to the right

-9v=15

v=15/-9

v=-1+2/3

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