7(v+3)=-3(2v-2)+3v

Solution for 7(v+3)=-3(2v-2)+3v equation:

7(v+3)=-3(2v-2)+3v

We move all terms to the left:

7(v+3)-(-3(2v-2)+3v)=0

We multiply parentheses

7v-(-3(2v-2)+3v)+21=0


We calculate terms in parentheses: -(-3(2v-2)+3v), so:

-3(2v-2)+3v

We add all the numbers together, and all the variables

3v-3(2v-2)

We multiply parentheses

3v-6v+6

We add all the numbers together, and all the variables

-3v+6

Back to the equation:

-(-3v+6)


We get rid of parentheses

7v+3v-6+21=0

We add all the numbers together, and all the variables

10v+15=0

We move all terms containing v to the left, all other terms to the right

10v=-15

v=-15/10

v=-1+1/2