7(v+3)=-3(2v-11+5v)

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Solution for 7(v+3)=-3(2v-11+5v) equation: 



7(v+3)=-3(2v-11+5v)

We move all terms to the left:

7(v+3)-(-3(2v-11+5v))=0

We add all the numbers together, and all the variables

7(v+3)-(-3(7v-11))=0

We multiply parentheses

7v-(-3(7v-11))+21=0



We calculate terms in parentheses: -(-3(7v-11)), so:

-3(7v-11)

We multiply parentheses

-21v+33

Back to the equation:

-(-21v+33)



We get rid of parentheses

7v+21v-33+21=0

We add all the numbers together, and all the variables

28v-12=0

We move all terms containing v to the left, all other terms to the right

28v=12

v=12/28

v=3/7

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