7(v+2)=-3(4v-2)+v

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Solution for 7(v+2)=-3(4v-2)+v equation: 



7(v+2)=-3(4v-2)+v

We move all terms to the left:

7(v+2)-(-3(4v-2)+v)=0

We multiply parentheses

7v-(-3(4v-2)+v)+14=0



We calculate terms in parentheses: -(-3(4v-2)+v), so:

-3(4v-2)+v

We add all the numbers together, and all the variables

v-3(4v-2)

We multiply parentheses

v-12v+6

We add all the numbers together, and all the variables

-11v+6

Back to the equation:

-(-11v+6)



We get rid of parentheses

7v+11v-6+14=0

We add all the numbers together, and all the variables

18v+8=0

We move all terms containing v to the left, all other terms to the right

18v=-8

v=-8/18

v=-4/9

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