7(v+2)=-3(3v-2)+2v

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Solution for 7(v+2)=-3(3v-2)+2v equation: 



7(v+2)=-3(3v-2)+2v

We move all terms to the left:

7(v+2)-(-3(3v-2)+2v)=0

We multiply parentheses

7v-(-3(3v-2)+2v)+14=0



We calculate terms in parentheses: -(-3(3v-2)+2v), so:

-3(3v-2)+2v

We add all the numbers together, and all the variables

2v-3(3v-2)

We multiply parentheses

2v-9v+6

We add all the numbers together, and all the variables

-7v+6

Back to the equation:

-(-7v+6)



We get rid of parentheses

7v+7v-6+14=0

We add all the numbers together, and all the variables

14v+8=0

We move all terms containing v to the left, all other terms to the right

14v=-8

v=-8/14

v=-4/7

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