7(u+6)=-7(2u-4)+3u

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Solution for 7(u+6)=-7(2u-4)+3u equation: 



7(u+6)=-7(2u-4)+3u

We move all terms to the left:

7(u+6)-(-7(2u-4)+3u)=0

We multiply parentheses

7u-(-7(2u-4)+3u)+42=0



We calculate terms in parentheses: -(-7(2u-4)+3u), so:

-7(2u-4)+3u

We add all the numbers together, and all the variables

3u-7(2u-4)

We multiply parentheses

3u-14u+28

We add all the numbers together, and all the variables

-11u+28

Back to the equation:

-(-11u+28)



We get rid of parentheses

7u+11u-28+42=0

We add all the numbers together, and all the variables

18u+14=0

We move all terms containing u to the left, all other terms to the right

18u=-14

u=-14/18

u=-7/9

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