7(u+1)=35

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Solution for 7(u+1)=35 equation: 



7(u+1)=35

We move all terms to the left:

7(u+1)-(35)=0

We multiply parentheses

7u+7-35=0

We add all the numbers together, and all the variables

7u-28=0

We move all terms containing u to the left, all other terms to the right

7u=28

u=28/7

u=4

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