7(t-5)+7t=7(2t+3)-10

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Solution for 7(t-5)+7t=7(2t+3)-10 equation:


Simplifying
7(t + -5) + 7t = 7(2t + 3) + -10

Reorder the terms:
7(-5 + t) + 7t = 7(2t + 3) + -10
(-5 * 7 + t * 7) + 7t = 7(2t + 3) + -10
(-35 + 7t) + 7t = 7(2t + 3) + -10

Combine like terms: 7t + 7t = 14t
-35 + 14t = 7(2t + 3) + -10

Reorder the terms:
-35 + 14t = 7(3 + 2t) + -10
-35 + 14t = (3 * 7 + 2t * 7) + -10
-35 + 14t = (21 + 14t) + -10

Reorder the terms:
-35 + 14t = 21 + -10 + 14t

Combine like terms: 21 + -10 = 11
-35 + 14t = 11 + 14t

Add '-14t' to each side of the equation.
-35 + 14t + -14t = 11 + 14t + -14t

Combine like terms: 14t + -14t = 0
-35 + 0 = 11 + 14t + -14t
-35 = 11 + 14t + -14t

Combine like terms: 14t + -14t = 0
-35 = 11 + 0
-35 = 11

Solving
-35 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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