7(t-2)+7t=7(2t+4)-9

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Solution for 7(t-2)+7t=7(2t+4)-9 equation: 



7(t-2)+7t=7(2t+4)-9

We move all terms to the left:

7(t-2)+7t-(7(2t+4)-9)=0

We add all the numbers together, and all the variables

7t+7(t-2)-(7(2t+4)-9)=0

We multiply parentheses

7t+7t-(7(2t+4)-9)-14=0



We calculate terms in parentheses: -(7(2t+4)-9), so:

7(2t+4)-9

We multiply parentheses

14t+28-9

We add all the numbers together, and all the variables

14t+19

Back to the equation:

-(14t+19)



We add all the numbers together, and all the variables

14t-(14t+19)-14=0

We get rid of parentheses

14t-14t-19-14=0

We add all the numbers together, and all the variables

-33!=0

There is no solution for this equation

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