7(t-2)+3t=5(2t+3)-12

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Solution for 7(t-2)+3t=5(2t+3)-12 equation: 



7(t-2)+3t=5(2t+3)-12

We move all terms to the left:

7(t-2)+3t-(5(2t+3)-12)=0

We add all the numbers together, and all the variables

3t+7(t-2)-(5(2t+3)-12)=0

We multiply parentheses

3t+7t-(5(2t+3)-12)-14=0



We calculate terms in parentheses: -(5(2t+3)-12), so:

5(2t+3)-12

We multiply parentheses

10t+15-12

We add all the numbers together, and all the variables

10t+3

Back to the equation:

-(10t+3)



We add all the numbers together, and all the variables

10t-(10t+3)-14=0

We get rid of parentheses

10t-10t-3-14=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation

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