7(t+3)=4(t-4)

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Solution for 7(t+3)=4(t-4) equation: 



7(t+3)=4(t-4)

We move all terms to the left:

7(t+3)-(4(t-4))=0

We multiply parentheses

7t-(4(t-4))+21=0



We calculate terms in parentheses: -(4(t-4)), so:

4(t-4)

We multiply parentheses

4t-16

Back to the equation:

-(4t-16)



We get rid of parentheses

7t-4t+16+21=0

We add all the numbers together, and all the variables

3t+37=0

We move all terms containing t to the left, all other terms to the right

3t=-37

t=-37/3

t=-12+1/3

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