7(t+2)=5(t+4)+2

Solution for 7(t+2)=5(t+4)+2 equation:

7(t+2)=5(t+4)+2

We move all terms to the left:

7(t+2)-(5(t+4)+2)=0

We multiply parentheses

7t-(5(t+4)+2)+14=0


We calculate terms in parentheses: -(5(t+4)+2), so:

5(t+4)+2

We multiply parentheses

5t+20+2

We add all the numbers together, and all the variables

5t+22

Back to the equation:

-(5t+22)


We get rid of parentheses

7t-5t-22+14=0

We add all the numbers together, and all the variables

2t-8=0

We move all terms containing t to the left, all other terms to the right

2t=8

t=8/2

t=4