7(t+2)-3(t-4)=6(t-7)+8

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Solution for 7(t+2)-3(t-4)=6(t-7)+8 equation:


7(t+2)-3(t-4)=6(t-7)+8

We simplify the equation to the form, which is simple to understand 
7(t+2)-3(t-4)=6(t-7)+8

Reorder the terms in parentheses
+(+7t+14)-3*(t-4)=6*(t-7)+8

Remove unnecessary parentheses
+7t+14-3+*(+t-4+)=+6+*(+t-7+)+8

Reorder the terms in parentheses
+7t+14+(-3t+12)=6*(t-7)+8

Remove unnecessary parentheses
+7t+14-3t+12=+6+*(+t-7+)+8

Reorder the terms in parentheses
+7t+14-3t+12=+(+6t-42)+8

Remove unnecessary parentheses
+7t+14-3t+12=+6t-42+8

We move all terms containing t to the left and all other terms to the right. 
+7t-3t-6t=-42+8-14-12

We simplify left and right side of the equation. 
-2t=-60

We divide both sides of the equation by -2 to get t. 
t=30

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