7(r-5)=5(r+3)

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Solution for 7(r-5)=5(r+3) equation:


Simplifying
7(r + -5) = 5(r + 3)

Reorder the terms:
7(-5 + r) = 5(r + 3)
(-5 * 7 + r * 7) = 5(r + 3)
(-35 + 7r) = 5(r + 3)

Reorder the terms:
-35 + 7r = 5(3 + r)
-35 + 7r = (3 * 5 + r * 5)
-35 + 7r = (15 + 5r)

Solving
-35 + 7r = 15 + 5r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-5r' to each side of the equation.
-35 + 7r + -5r = 15 + 5r + -5r

Combine like terms: 7r + -5r = 2r
-35 + 2r = 15 + 5r + -5r

Combine like terms: 5r + -5r = 0
-35 + 2r = 15 + 0
-35 + 2r = 15

Add '35' to each side of the equation.
-35 + 35 + 2r = 15 + 35

Combine like terms: -35 + 35 = 0
0 + 2r = 15 + 35
2r = 15 + 35

Combine like terms: 15 + 35 = 50
2r = 50

Divide each side by '2'.
r = 25

Simplifying
r = 25

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