7(r+3)-19=8(r-8)+63

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Solution for 7(r+3)-19=8(r-8)+63 equation: 



7(r+3)-19=8(r-8)+63

We move all terms to the left:

7(r+3)-19-(8(r-8)+63)=0

We multiply parentheses

7r-(8(r-8)+63)+21-19=0



We calculate terms in parentheses: -(8(r-8)+63), so:

8(r-8)+63

We multiply parentheses

8r-64+63

We add all the numbers together, and all the variables

8r-1

Back to the equation:

-(8r-1)



We add all the numbers together, and all the variables

7r-(8r-1)+2=0

We get rid of parentheses

7r-8r+1+2=0

We add all the numbers together, and all the variables

-1r+3=0

We move all terms containing r to the left, all other terms to the right

-r=-3

r=-3/-1

r=+3

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