7(q-5)=2(q+5)

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Solution for 7(q-5)=2(q+5) equation:


Simplifying
7(q + -5) = 2(q + 5)

Reorder the terms:
7(-5 + q) = 2(q + 5)
(-5 * 7 + q * 7) = 2(q + 5)
(-35 + 7q) = 2(q + 5)

Reorder the terms:
-35 + 7q = 2(5 + q)
-35 + 7q = (5 * 2 + q * 2)
-35 + 7q = (10 + 2q)

Solving
-35 + 7q = 10 + 2q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-2q' to each side of the equation.
-35 + 7q + -2q = 10 + 2q + -2q

Combine like terms: 7q + -2q = 5q
-35 + 5q = 10 + 2q + -2q

Combine like terms: 2q + -2q = 0
-35 + 5q = 10 + 0
-35 + 5q = 10

Add '35' to each side of the equation.
-35 + 35 + 5q = 10 + 35

Combine like terms: -35 + 35 = 0
0 + 5q = 10 + 35
5q = 10 + 35

Combine like terms: 10 + 35 = 45
5q = 45

Divide each side by '5'.
q = 9

Simplifying
q = 9

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