7(p+q+4)=7p+7q

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Solution for 7(p+q+4)=7p+7q equation:


Simplifying
7(p + q + 4) = 7p + 7q

Reorder the terms:
7(4 + p + q) = 7p + 7q
(4 * 7 + p * 7 + q * 7) = 7p + 7q
(28 + 7p + 7q) = 7p + 7q

Add '-7p' to each side of the equation.
28 + 7p + -7p + 7q = 7p + -7p + 7q

Combine like terms: 7p + -7p = 0
28 + 0 + 7q = 7p + -7p + 7q
28 + 7q = 7p + -7p + 7q

Combine like terms: 7p + -7p = 0
28 + 7q = 0 + 7q
28 + 7q = 7q

Add '-7q' to each side of the equation.
28 + 7q + -7q = 7q + -7q

Combine like terms: 7q + -7q = 0
28 + 0 = 7q + -7q
28 = 7q + -7q

Combine like terms: 7q + -7q = 0
28 = 0

Solving
28 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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