7(n-5)=-2(-5+4n)+6n

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Solution for 7(n-5)=-2(-5+4n)+6n equation: 



7(n-5)=-2(-5+4n)+6n

We move all terms to the left:

7(n-5)-(-2(-5+4n)+6n)=0

We add all the numbers together, and all the variables

7(n-5)-(-2(4n-5)+6n)=0

We multiply parentheses

7n-(-2(4n-5)+6n)-35=0



We calculate terms in parentheses: -(-2(4n-5)+6n), so:

-2(4n-5)+6n

We add all the numbers together, and all the variables

6n-2(4n-5)

We multiply parentheses

6n-8n+10

We add all the numbers together, and all the variables

-2n+10

Back to the equation:

-(-2n+10)



We get rid of parentheses

7n+2n-10-35=0

We add all the numbers together, and all the variables

9n-45=0

We move all terms containing n to the left, all other terms to the right

9n=45

n=45/9

n=5

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