7(n-5)+6(-6+4n)=1-4n+n-4

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Solution for 7(n-5)+6(-6+4n)=1-4n+n-4 equation: 



7(n-5)+6(-6+4n)=1-4n+n-4

We move all terms to the left:

7(n-5)+6(-6+4n)-(1-4n+n-4)=0

We add all the numbers together, and all the variables

7(n-5)+6(4n-6)-(-3n-3)=0

We multiply parentheses

7n+24n-(-3n-3)-35-36=0

We get rid of parentheses

7n+24n+3n+3-35-36=0

We add all the numbers together, and all the variables

34n-68=0

We move all terms containing n to the left, all other terms to the right

34n=68

n=68/34

n=2

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