7(n-4)(n+4)=0

Solution for 7(n-4)(n+4)=0 equation:

Simplifying
7(n + -4)(n + 4) = 0

Reorder the terms:
7(-4 + n)(n + 4) = 0

Reorder the terms:
7(-4 + n)(4 + n) = 0

Multiply (-4 + n) * (4 + n)
7(-4(4 + n) + n(4 + n)) = 0
7((4 * -4 + n * -4) + n(4 + n)) = 0
7((-16 + -4n) + n(4 + n)) = 0
7(-16 + -4n + (4 * n + n * n)) = 0
7(-16 + -4n + (4n + n2)) = 0

Combine like terms: -4n + 4n = 0
7(-16 + 0 + n2) = 0
7(-16 + n2) = 0
(-16 * 7 + n2 * 7) = 0
(-112 + 7n2) = 0

Solving
-112 + 7n2 = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '112' to each side of the equation.
-112 + 112 + 7n2 = 0 + 112

Combine like terms: -112 + 112 = 0
0 + 7n2 = 0 + 112
7n2 = 0 + 112

Combine like terms: 0 + 112 = 112
7n2 = 112

Divide each side by '7'.
n2 = 16

Simplifying
n2 = 16

Take the square root of each side:
n = {-4, 4}