7(n-2)=6(n-5)+2

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Solution for 7(n-2)=6(n-5)+2 equation: 



7(n-2)=6(n-5)+2

We move all terms to the left:

7(n-2)-(6(n-5)+2)=0

We multiply parentheses

7n-(6(n-5)+2)-14=0



We calculate terms in parentheses: -(6(n-5)+2), so:

6(n-5)+2

We multiply parentheses

6n-30+2

We add all the numbers together, and all the variables

6n-28

Back to the equation:

-(6n-28)



We get rid of parentheses

7n-6n+28-14=0

We add all the numbers together, and all the variables

n+14=0

We move all terms containing n to the left, all other terms to the right

n=-14

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