7(n-2)=6(3n-5)-3n

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Solution for 7(n-2)=6(3n-5)-3n equation: 



7(n-2)=6(3n-5)-3n

We move all terms to the left:

7(n-2)-(6(3n-5)-3n)=0

We multiply parentheses

7n-(6(3n-5)-3n)-14=0



We calculate terms in parentheses: -(6(3n-5)-3n), so:

6(3n-5)-3n

We add all the numbers together, and all the variables

-3n+6(3n-5)

We multiply parentheses

-3n+18n-30

We add all the numbers together, and all the variables

15n-30

Back to the equation:

-(15n-30)



We get rid of parentheses

7n-15n+30-14=0

We add all the numbers together, and all the variables

-8n+16=0

We move all terms containing n to the left, all other terms to the right

-8n=-16

n=-16/-8

n=+2

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