7(n-2)+8=(n-4)-2

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Solution for 7(n-2)+8=(n-4)-2 equation: 



7(n-2)+8=(n-4)-2

We move all terms to the left:

7(n-2)+8-((n-4)-2)=0

We multiply parentheses

7n-((n-4)-2)-14+8=0



We calculate terms in parentheses: -((n-4)-2), so:

(n-4)-2

We get rid of parentheses

n-4-2

We add all the numbers together, and all the variables

n-6

Back to the equation:

-(n-6)



We add all the numbers together, and all the variables

7n-(n-6)-6=0

We get rid of parentheses

7n-n+6-6=0

We add all the numbers together, and all the variables

6n=0

n=0/6

n=0

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