7(n+3)=(n-4)+5

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Solution for 7(n+3)=(n-4)+5 equation: 



7(n+3)=(n-4)+5

We move all terms to the left:

7(n+3)-((n-4)+5)=0

We multiply parentheses

7n-((n-4)+5)+21=0



We calculate terms in parentheses: -((n-4)+5), so:

(n-4)+5

We get rid of parentheses

n-4+5

We add all the numbers together, and all the variables

n+1

Back to the equation:

-(n+1)



We get rid of parentheses

7n-n-1+21=0

We add all the numbers together, and all the variables

6n+20=0

We move all terms containing n to the left, all other terms to the right

6n=-20

n=-20/6

n=-3+1/3

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