7(n+2)=25-(3n+4)

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Solution for 7(n+2)=25-(3n+4) equation: 



7(n+2)=25-(3n+4)

We move all terms to the left:

7(n+2)-(25-(3n+4))=0

We multiply parentheses

7n-(25-(3n+4))+14=0



We calculate terms in parentheses: -(25-(3n+4)), so:

25-(3n+4)

determiningTheFunctionDomain
-(3n+4)+25

We get rid of parentheses

-3n-4+25

We add all the numbers together, and all the variables

-3n+21

Back to the equation:

-(-3n+21)



We get rid of parentheses

7n+3n-21+14=0

We add all the numbers together, and all the variables

10n-7=0

We move all terms containing n to the left, all other terms to the right

10n=7

n=7/10

n=7/10

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