7(n+2)+3(2n-4)=

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Solution for 7(n+2)+3(2n-4)= equation:


Simplifying
7(n + 2) + 3(2n + -4) = 0

Reorder the terms:
7(2 + n) + 3(2n + -4) = 0
(2 * 7 + n * 7) + 3(2n + -4) = 0
(14 + 7n) + 3(2n + -4) = 0

Reorder the terms:
14 + 7n + 3(-4 + 2n) = 0
14 + 7n + (-4 * 3 + 2n * 3) = 0
14 + 7n + (-12 + 6n) = 0

Reorder the terms:
14 + -12 + 7n + 6n = 0

Combine like terms: 14 + -12 = 2
2 + 7n + 6n = 0

Combine like terms: 7n + 6n = 13n
2 + 13n = 0

Solving
2 + 13n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 13n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 13n = 0 + -2
13n = 0 + -2

Combine like terms: 0 + -2 = -2
13n = -2

Divide each side by '13'.
n = -0.1538461538

Simplifying
n = -0.1538461538

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