7(m-3)+5=4(2-m)+3

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Solution for 7(m-3)+5=4(2-m)+3 equation: 



7(m-3)+5=4(2-m)+3

We move all terms to the left:

7(m-3)+5-(4(2-m)+3)=0

We add all the numbers together, and all the variables

7(m-3)-(4(-1m+2)+3)+5=0

We multiply parentheses

7m-(4(-1m+2)+3)-21+5=0



We calculate terms in parentheses: -(4(-1m+2)+3), so:

4(-1m+2)+3

We multiply parentheses

-4m+8+3

We add all the numbers together, and all the variables

-4m+11

Back to the equation:

-(-4m+11)



We add all the numbers together, and all the variables

7m-(-4m+11)-16=0

We get rid of parentheses

7m+4m-11-16=0

We add all the numbers together, and all the variables

11m-27=0

We move all terms containing m to the left, all other terms to the right

11m=27

m=27/11

m=2+5/11

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