7(m+2)-5=1/3(21m+9)-6

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Solution for 7(m+2)-5=1/3(21m+9)-6 equation: 



7(m+2)-5=1/3(21m+9)-6

We move all terms to the left:

7(m+2)-5-(1/3(21m+9)-6)=0



Domain of the equation: 3(21m+9)-6)!=0

m∈R



We multiply parentheses

7m-(1/3(21m+9)-6)+14-5=0

We multiply all the terms by the denominator


7m*3(21m+9)+14*3(21m+9)-6)-5*3(21m-6)-(1+9)-6)=0

We add all the numbers together, and all the variables

7m*3(21m+9)+14*3(21m+9)-6)-5*3(21m-6)-10-6)=0

We add all the numbers together, and all the variables

7m*3(21m+9)+14*3(21m+9)-6)-5*3(21m=0

Wy multiply elements

21m^2(2+42m(2-6)-5*3(21m=0

We add all the numbers together, and all the variables

21m^2(2+42m(-4)-5*3(21m=0

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