7(m+1)=4(m-3)

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Solution for 7(m+1)=4(m-3) equation: 



7(m+1)=4(m-3)

We move all terms to the left:

7(m+1)-(4(m-3))=0

We multiply parentheses

7m-(4(m-3))+7=0



We calculate terms in parentheses: -(4(m-3)), so:

4(m-3)

We multiply parentheses

4m-12

Back to the equation:

-(4m-12)



We get rid of parentheses

7m-4m+12+7=0

We add all the numbers together, and all the variables

3m+19=0

We move all terms containing m to the left, all other terms to the right

3m=-19

m=-19/3

m=-6+1/3

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